hw 0
(Not graded.) Read Sections 0.1-0.3 and 0.5-0.6 in Follandโs book. Note: I expect you to have seen much but not necessarily all of this material in earlier courses. It is not necessary to know everything by heart right now. However, in order to succeed in the class, you need to be able to read mathematical material at this level of abstraction and (lack of) detail.
Approaching 597
Let be an infinite (not necessarily countable) set, and a function. Suppose that for every integer there exist finite subsets and such that:
(i) for all ;
(ii) ;
(iii) .
Prove that for any , there exists a finite subset such that
We first take s.t. for all , as given by the conditions.
Now we define and .
Let . This is a real number since is finite.
Case 1: if , then we need to fill in more elements whose image under sum up to be positive to make the sum close to 597 from below.
We then take a finite set s.t. .
Since , we have
and since , we have
By (1) and (2), it is clear that
(3) means that the elements in have big enough image sum to fill the gap. And by definition, for all , we have . This means that each element in this finite takes up only a small portion of the sum, bounded by . Together with (3), it follows that there is some subset s.t. . So for the finite set , we have
Case 2: if , then we need to fill in more elements whose image under sum up to be negative to make the sum close to 597 from above.
We then take finite s.t. .
For the same reason as case 1, we get
And by definition, for all , we have . Together with (5), it follows that there is some subset s.t. . So for the finite set , we have
Case 3: , then we are done.
This finishes the proof of the statement.
โก
Limsup and Liminf
Let be a nonempty set, and subsets of . Define a sequence of subsets of by
Characterize the sets and (see ยง0.1 in Folland for notation).
By definition,
For each , there are infinitely many such that is prime, and also there are infinitely many such that is not prime. So . Therefore
By definition,
For each , there are infinitely many such that is prime, and also there are infinitely many such that is not prime. So . Therefore
Polynomial Convergence
Let be a function with the property that for every polynomial
with integer coefficients, we have that
Does it follow that as ? In other words, given , does there exist such that whenever ? Give a proof or a counterexample.
Consider this function:
Let be arbitrary polynomial with integer coefficients. Then there must be at most finite such that . This is guaranteed by the asymptotic behavior of polynomial and exponential function: . So there exists some s.t. for all , therefore is eventually 0.
Also, there must be at most finite such that , i.e. . This is guaranteed by the asymptotic behavior of polynomial and logarithmic function: . So there exists some s.t. for all , therefore is eventually 0.
This confirms that for any polynomial with integer coefficients.
Then we consider the sequence . For any , , so the sequential limit is . This completes the counterexample.
1 Problem solving
Recall: Given mspace ไปฅๅ mble, ๆไปฌๅฏไปฅ define distribution function:
by
Chebyshevs ineq:
for .
Today: Problem Solving
ๅฏนไบไปปๆ , ๆไปฌๆ:
ๅทฆ่พนๆฏ integral on , ๅณ่พนๆฏ integral on .
Sketch: Step 1: simple simple.
โก
Write
where disjoint, This implies:
Then
ไป่
Step 2: general.
Use: simple functions s.t. .
MCT
Also,
ไป่ MCT
, ไปฅๅ increasing union.
Let be abs ctn. Suppose ไปฅๅ .
Show that the limit
exists, ๅนถ compute it.
What could the limit be? Must be .
Use FTOC, can recover from .
ไฝฟ็จ Hรถlder with (Cauchy-Swartz):
ไป่
Use fact: s.t. for all we have .
(Proof of this fact: use approx by simple functions ๅฏๅพ).
็ถๅ use approx by simple functions, apply to , , , ไบๆฏๅพๅฐ
Let be a function.
Assume: ๅฏนไบ , ้ฝๅญๅจ Lebesgue mble functions s.t.
ๅนถไธ
Prove that: ไนๆฏ Lebesgue mble ็, ๅนถไธ .
By assumption: Given , ๅญๅจ s.t.
Idea: ?
ๆไปฌๅบ่ฏฅ try to prove: for a.e. ้ฝๆ .
Use Fatouโs Lemma:
่ , ๅ ่ This means:
ไธๆไปฌ็ฅ้
ไป่
This proves that, is Lebesgue measurable.
โก
Prove that:
for every bounded Borel set .
Step 1: ๆฏไธไธช interval.
ไป่
Step 2: ๆฏไธไธช finite union of disjoint open intervals.
Same as Step 1.
Step 3: General Case.
Fix .
Then by outer regularity: ๅญๅจ some ไธบ finite disjoint union of open intervals, ไฝฟๅพ
ไป่
ๅ ่
for all . ๅนถไธ By step 2:
ๅ ่
Since arbitrary, ๅพ่ฏ.
โก
Let be a Borel set, with .
Set be mble, nonneg, ๅนถไธ .
Prove that: ๅญๅจ s.t.
Claim 1: STS to assume simple.
Proof of Claim 1: ๅฏนไบ , can find seq of simple functions , s.t. .
By MCT,
โก
2 problem solving-III
Let .
Assume
for all , .
Now show: for a.e. .
WLOG ๅฏไปฅๅ่ฎพ ๆฏ nonneg ็. ().
WTS: for a.e. .
Claim 1: by LDT, it STS:
for all .
ๆไปฌ try Cauchy Swartz:
ๆไปฌ็ฅ้: ๅทฆ่พน , ่ๅณ่พน็ฌฌไธ้กน ๆฏๅฏไปฅ่ฎก็ฎ็: ็ญไบ .
ไบๆฏ, ๆไปฌๅพๅฐ
ไป่:
็ถๅ by LDT:
for a.e. . ๅ ่
ไบๆฏ
โก
Prove or disprove: ๅฏนไบ bounded open set , ๅฎ็ boundary ๆฏๅฆไธๅฎๆปก่ถณ ?
Astonishingly ่ฟไธช้ฎ้ข็ๅ็ญๆฏๅฆๅฎ็. ๆไปฌๅฏไปฅๆ้
3 extra topics
3.1 Minkowski ineq for integral
3.2 convolution
ๆไปฌๅทฒ็ป่ฏๆไบ, for ,
What about for ? ็ญๆกไนๆฏ true ็, ๆไปฌ้่ฆ็จๅฐ convolution ๆฅ่ฏๆ.
4 Use FTC and Tonelli for series
Let , be a sequence of functions that are absolutely continuous on the interval . Suppose that there is a , such that the series is convergent, and
(a) Show that is convergent for all . (b) Let . Show that is absolutely continuous on and
โ โ โ โ โ โ โ โ โ
5 Use FTC and Holder
Let be absolutely continuous, satisfy and . Show that
exists and determine the value of this limit. โ โ โ โ โ โ โ โ โ
6 Use density of compactly supported continuous functions in a suitable space
Let be a real Lebesgue measurable function on the interval such that . Show that for any , there is a continuous function on such that . โ โ โ โ โ โ โ โ โ
7 Use one of the convergence theorems
Let A be a sequence of measurable subsets of such that , where stands for the Lebesgue measure. (a) Prove that there exists which belongs to infinitely many of the sets . (b) Does there necessarily exist a point which belongs to any of the sets , except finitely many? โ โ โ โ โ โ โ โ โ
8 How can we recover E from its indicator function
Let . Show that the characteristic function is the limit of a sequence of continuous functions if and only if is both and .โ โ โ โ โ โ โ โ โ
9 be an artisan
Let be a positive function of bounded variation. (a) Show that if , then the function is also of bounded variation on . (b) Give an example of a positive function of bounded variation such that is integrable but not of bounded variation.โ โ โ โ โ โ โ โ โ
10 Use a suitable theorem allowing you to differentiate under the integral sign
Let be a real Lebesgue measurable function on the interval such that . For define a function by
โ โ โ โ โ โ โ โ โ
(a) Prove that the function is twice continuously differentiable and that for all , i.e. the function is convex. (b) Prove that if is a non-constant function, i.e. for all constants , then .โ โ โ โ โ โ โ โ โ
11 Use DCT
Let
Find:
โ โ โ โ โ โ โ โ โ
12 Use Egoroff and Hรถlder
Let be a sequence of functions in , which converge almost everywhere to a function , and suppose that there is a constant such that for all . Show that for every the conjugate of ,
Is the statement true for ? (Hint: you may want to use Egorovโs Theorem.)โ โ โ โ โ โ โ โ โ
13 Read up on HL
Let be a locally integrable function on and the corresponding Hardy-Littlewood maximal function
where denotes the ball centered at with radius . a) Show that if is integrable on then . b) Let be the function
Show that is not integrable on , but .โ โ โ โ โ โ โ โ โ
14 Use density of such functions g somewhere, and then Hรถlder.
Fix . Let , where is a measurable subset of . Assume that
for all compactly supported continuous functions . Is for almost every in ? If your answer is positive, prove it. Otherwise, given a counterexample.โ โ โ โ โ โ โ โ โ
15 Fubini and Tonelli
Suppose that , is a real valued Lebesgue measurable square integrable function. (a) Prove that for any , the inequality holds for all . (b) Express the double integral
as an integral over the region . (c) Show using your work from (a) and (b) that , is integrable and
Hint: Use the inequality in (a) with .โ โ โ โ โ โ โ โ โ
16 Try a very nice function f first
Let be a sequence of continuous, strictly positive functions on which converges uniformly to the function . Suppose that all the functions are integrable. Is
Justify your answer.โ โ โ โ โ โ โ โ โ
17 Use Lebesgue. Can you get the same equality for more sets E?
Let be a function such that for any measurable set of Lebesgue measure .99. Prove that a.e.โ โ โ โ โ โ โ โ โ
18 Lebesgue
Let , for any finite interval . Assume that
for all and . Show that for a.e. .โ โ โ โ โ โ โ โ โ
19 Integration can be a trick to prove that a nonnegative function canโt be identically zero.
Let and be nonnegative functions in . Suppose that each function is positive on some set of positive measure. (However, there need not be a single set of positive measure where both functions are positive.) Prove that the convolution
is positive on some set of positive measure.โ โ โ โ โ โ โ โ โ
20 Check what happens on some set with
Let be a measurable subset of such that . Let with . Show that
Here .โ โ โ โ โ โ โ โ โ
21 Use distribution functions
Let be a measurable function which has the property that
(a) Show that is integrable for . (b) Give an example of a function satisfying the above for which is not integrable.โ โ โ โ โ โ โ โ โ